Q64 / 180 · COMEDK 2012 · Mathematics

Equation of the chord of the circle $x^{2}+y^{2}+4 x-6 y-9=0$ bisected at $(0,1)$ is

  • Correct answer
    A
    $y-1=x$
  • B
    $y+1=x$
  • C
    $y+1=2 x$
  • D
    $y-1=3 x$

Solution

Given, equation of circle is $$ x^{2}+y^{2}+4 x-6 y-9=0 $$ Here, $T=S_{1}$ $x(0)+y(1)+2(x+0)-3(y+1)-9=y+1+0-6-9$ $\Rightarrow y+2 x-3 y-3-9=1-15$ $\Rightarrow \quad 2 x-2 y-12=1-15$ $\Rightarrow \quad 2 x-2 y+2=0$ $\Rightarrow \quad x-y+1=0$

Hence, the correct answer is option: 'A'.

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