Q98 / 150 · MHT CET 2009 · Mathematics

Equation of tangent to the parabola $y^{2}=16 x$ at $P(3,6)$ is

A
$4 x-3 y+12=0$
Correct answer
B
$3 y-4 x-12=0$
C
$4 x-3 y-24=0$
D
$3 y-x-24=0$

Solution

Equation of tangent to parabola $y^{2}=16 x$ at $P(3,6)$ is $\begin{aligned} & & 6 y &=8(x+3) \\ \Rightarrow & & 3 y &=4 x+12 \\ \Rightarrow & 3 y-4 x &-12 &=0 \end{aligned}$

Hence, the correct answer is option: 'B'.

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