Q105 / 160 · AP EAMCET 2022 (07 Jul Shift 2) · Mathematics

Equation of tangent to the curve $y=x+\frac{4}{x^2}$ which is parallel to $X$-axis is

  • A
    $y=8$
  • B
    $y=0$
  • Correct answer
    C
    $y=3$
  • D
    $y=2$

Solution

$$ y=x+\frac{4}{x^2} \Rightarrow y^{\prime}=1-\frac{8}{x^3} $$ As tangent is parallel to $X$-axis, $y^{\prime}=0 \Rightarrow x=2$ At $x=2, y=3$. $\therefore$ Equation of tangent is $y=3$

Hence, the correct answer is option: 'C'.

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