Q105 / 160 · AP EAMCET 2022 (07 Jul Shift 2) · Mathematics
Equation of tangent to the curve $y=x+\frac{4}{x^2}$ which is parallel to $X$-axis is
- A$y=8$
- B$y=0$
- Correct answerC$y=3$
- D$y=2$
Solution
$$
y=x+\frac{4}{x^2} \Rightarrow y^{\prime}=1-\frac{8}{x^3}
$$
As tangent is parallel to $X$-axis, $y^{\prime}=0 \Rightarrow x=2$
At $x=2, y=3$.
$\therefore$ Equation of tangent is $y=3$
Hence, the correct answer is option: 'C'.