Q76 / 120 · JEE Main 2007 · Mathematics
$\int \frac{d x}{\cos x+\sqrt{3} \sin x}$ equals
- Correct answerA$\frac{1}{2} \log \tan \left(\frac{x}{2}+\frac{\pi}{12}\right)+c$
- B$\frac{1}{2} \log \tan \left(\frac{x}{2}-\frac{\pi}{12}\right)+c$
- C$\log \tan \left(\frac{\mathrm{x}}{2}+\frac{\pi}{12}\right)+\mathrm{c}$
- D$\log \tan \left(\frac{\mathrm{x}}{2}-\frac{\pi}{12}\right)+\mathrm{c}$
Solution
$\int \frac{d x}{\cos x+\sqrt{3} \sin x}$
$=\frac{1}{2} \int \sec \left(x-\frac{\pi}{3}\right) d x$
$=\frac{1}{2} \log \tan \left(\frac{x}{2}-\frac{\pi}{6}+\frac{\pi}{4}\right)+c$
$=\frac{1}{2} \log \tan \left(\frac{x}{2}+\frac{\pi}{12}\right)+c$.
Hence, the correct answer is option: 'A'.