Q11 / 160 · WBJEE 2012 · Chemistry

Equal weights of $\mathrm{CH}_{4}$ and $\mathrm{H}_{2}$ are mixed in an empty container at $25^{\circ} \mathrm{C}$. the fraction of the total pressure exerted by $\mathrm{H}_{2}$ is

  • A
    $1 / 9$
  • B
    $1 / 2$
  • Correct answer
    C
    $8 / 9$
  • D
    $16 / 17$

Solution

Ratio of number of moles of $\mathrm{CH}_{4}$ and $\mathrm{H}_{2}$ are $$ \begin{array}{r} \mathrm{CH}_{4}: \mathrm{H}_{2}=\frac{x}{16} ; \frac{x}{2} \\ =1: 8 \end{array} $$ Hence, partial pressure exerted by $$ \mathrm{H}_{2}=\frac{8}{1+8} \times p_{\text {total }}=\frac{8}{9} \times p_{\text {lotal }} $$

Hence, the correct answer is option: 'C'.

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