Electric field at a distance $r$ from an infinitely long uniformly charged straight conductor, having linear charge density $\lambda$ is $E_1$. Another uniformly charged conductor having same linear charge density $\lambda$ is bent. into a semicircle of radius $r$. The electric field at its centre is $E_2$. Then

• A

  $E_2=\pi r E_1$
• B

  $E_2=\frac{E_1}{r}$
• Correct answer
  C

  $E_1=E_2$
• D

  $E_1=\pi r E_2$

Hence, the correct answer is option: 'C'.