Q141 / 150 · MHT CET 2025 (23 Apr Shift 2) · Physics

During thermodynamic process, the increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?

  • A
    Isothermal
  • Correct answer
    B
    Adiabatic
  • C
    Isochoric
  • D
    Isobaric

Solution

The First Law of Thermodynamics states that the change in internal energy ΔU equals the heat added to the system Q plus the work done on the system W: $\Delta U = Q + W$.

Given that ΔU = W, substitution yields $W = Q + W$, which simplifies to $Q = 0$. A process with no heat exchange (Q = 0) is adiabatic.

Other processes are incompatible: isothermal implies $\Delta U = 0$ but not necessarily W = 0; isochoric gives W = 0 but not necessarily $\Delta U = 0$; isobaric has no inherent constraint linking ΔU and W.

The process is adiabatic, corresponding to option B.

Hence, the correct answer is option: 'B'.

Relevant Questions