Q169 / 180 · KCET 2020 · Physics
During a $\beta^{-}$-decay
- Aan atomic electron is ejected
- Ban electron which is already present within the nucleus is ejected
- Correct answerCa neutron in the nucleus decays emitting an electron
- Da proton in the nucleus decays emitting an electron
Solution
The process of $\beta^{-}$decay is shown below
${ }_{Z}^{A} X \stackrel{\beta^{-}}{\longrightarrow}{ }_{Z+1}^{A} Y+e^{-}+\bar{v}+\text { energy }$
Thus, in this decay a neutron inside the nucleus decays into a proton with the emission of an electron $e^{-}$and a particle called anti-neutrino $(\bar{v})$.
Hence, the correct answer is option: 'C'.