Q76 / 150 · MHT CET 2008 · Mathematics

Dual of $\left(x^{\prime} \vee y^{\prime}\right)=x \wedge y$ is

  • A
    $\left(x^{\prime} \vee y^{\prime}\right)=x \vee y_{1}$
  • Correct answer
    B
    $\left(x^{\prime} \wedge y^{\prime}\right)^{\prime}=x \vee y$
  • C
    $\left(x^{\prime} \wedge y^{\prime}\right)^{\prime}=x \wedge y$
  • D
    None of the above

Solution

Dual of $\left(x^{\prime} \vee y^{\prime}\right)^{\prime}=x \wedge y$ is $\left(x^{\prime} \wedge y^{\prime}\right)^{\gamma}=x \vee y$

Hence, the correct answer is option: 'B'.

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