Q5 / 90 · JEE Main 2014 (09 Apr Online) · Chemistry

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

  • A
    2.50 M
  • B
    1.00 M
  • Correct answer
    C
    2.00 M
  • D
    4.00 M

Solution

Mass of compound  =120g ;   moles= 120g 60g/mole =2

Mass of solution  = 1 0 0 0 + 1 2 0 = 1 1 2 0 g

Volume of solution  mass d = 1120g 1.12g/mL =1000mL

Molarity  = 2  moles 1 0 0 0  mL × 1 0 0 0 mL

              = 2 M (no of moles/Litre)

Hence, the correct answer is option: 'C'.

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