Q41 / 180 · AIIMS 2011 · Chemistry

Decreasing order of bond angle is

  • Correct answer
    A
    $\mathrm{BeCl}_2>\mathrm{NO}_2>\mathrm{SO}_2$
  • B
    $\mathrm{BeCl}_2>\mathrm{SO}_2>\mathrm{NO}_2$
  • C
    $\mathrm{SO}_2>\mathrm{BeCl}_2>\mathrm{NO}_2$
  • D
    $\mathrm{SO}_2>\mathrm{NO}_2>\mathrm{BeCl}_2$

Solution

Compound: $\mathrm{BeCl}_2>\mathrm{NO}_2>\mathrm{SO}_2$ Angle : $180^{\circ}>132^{\circ}>119.5^{\circ}$

Hence, the correct answer is option: 'A'.

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