Q183 / 240 · KCET 2026 · Physics
Current flowing through a wire decreases linearly from $10$ A to zero in $4$ s as shown in the graph. Find the total charge flowing through the wire in the given time interval.
- A$40$ C
- Correct answerB$20$ C
- C$10$ C
- D$80$ C
Solution
The total charge flowing through the wire is given by the area under the current-time ($I-t$) graph.
From the given graph, the area is a triangle with base $t = 4 \text{ s}$ and height $I = 10 \text{ A}$.
$Q = \text{Area of triangle} = \dfrac{1}{2} \times \text{base} \times \text{height}$
$Q = \dfrac{1}{2} \times 4 \times 10 = 20 \text{ C}$
Therefore, the total charge flowing through the wire is $20 \text{ C}$.
Answer: $20$ C
From the given graph, the area is a triangle with base $t = 4 \text{ s}$ and height $I = 10 \text{ A}$.
$Q = \text{Area of triangle} = \dfrac{1}{2} \times \text{base} \times \text{height}$
$Q = \dfrac{1}{2} \times 4 \times 10 = 20 \text{ C}$
Therefore, the total charge flowing through the wire is $20 \text{ C}$.
Answer: $20$ C
Hence, the correct answer is option: 'B'.