Q48 / 200 · NEET 2010 (Screening) · Chemistry

$A B$ crystallizes in a body centred cubic lattice with edge length ' $a$ ' equal to $387 \mathrm{pm}$. The distance between two oppositively charged ions in the lattice is

  • Correct answer
    A
    $335 \mathrm{pm}$
  • B
    $250 \mathrm{pm}$
  • C
    $200 \mathrm{pm}$
  • D
    $300 \mathrm{pm}$

Solution

For body centred cubic (bcc) lattice, distance between two oppositely charged ions, $$ \begin{aligned} \mathrm{d} & =\frac{\sqrt{3} \mathrm{a}}{2}=\frac{\sqrt{3} \times 387}{2} \mathrm{pm} \\ & =335.15 \mathrm{pm} \end{aligned} $$

Hence, the correct answer is option: 'A'.

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