Q160 / 160 · WBJEE 2015 · Physics
Consider two particles of different masses, In which of the following situations the heavier of the two particles will have smaller de-Broglie wavelength?
- Correct answerABoth have a free fall through the same height
- Correct answerBBoth move with the same kinetic energy
- CBoth move with the same linear momentum
- Correct answerDBoth move with the same speed
Solution
The de-Broglie equation is
$$
\begin{aligned}
\lambda &=\frac{h}{m v}=\frac{h}{\sqrt{2 m k}} \Rightarrow m=\frac{h}{\lambda v} \\
\Rightarrow \quad m \propto \frac{1}{\lambda}, \text { if } \frac{h}{v} &=\mathrm{constant}
\end{aligned}
$$
Again, $\frac{h}{v}$ will be constant only when $v$ is constant
Thus, in present case the de-Broglie wavelength of heavier particle will be smaller. When the velocities of two particles will be same or both move with same kinetic energy(K).
Hence, the correct answer is options: 'A', 'B', 'D'.