Q12 / 160 · TS EAMCET 2017 · Chemistry
Consider the single electrode process $4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightleftharpoons 2 \mathrm{H}_2$ catalysed by platinum black electrode in $\mathrm{HCl}$ electrolyte. The potential of the electrode is $-0.059 \mathrm{~V}$. SHE. What is the concentration of the acid in the hydrogen half cell if the $\mathrm{H}_2$ pressure is $1 \mathrm{bar}$ ?
$$
4 \mathrm{H}^{+}+4 e^{-} \rightleftharpoons 2 \mathrm{H}_2
$$
- A$1 \mathrm{M}$
- B$10 \mathrm{M}$
- Correct answerC$0.1 \mathrm{M}$
- D$0.01 \mathrm{M}$
Solution
$4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightleftharpoons 2 \mathrm{H}_2$
$$
\begin{aligned}
& E=E^{\circ}-\frac{0.059}{n} \log \frac{p \mathrm{H}_2}{\left[\mathrm{H}^{+}\right]^4} \\
& -0.059=0-\frac{0.059}{4} \log \frac{1}{\left[\mathrm{H}^{+}\right]^4} \\
& =\left[\mathrm{H}^{+}\right]=10^{-1}=0.1 \mathrm{M}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.