Q177 / 270 · NDA 2016 (Phase 1) · Mathematics
Consider the lines $y=3 x, y=6 x$ and $y=9$
What is the area of the triangle formed by these lines?
- Correct answerA$\frac{27}{4}$ square units
- B$\frac{27}{2}$ square units
- C$\frac{19}{4}$ square units
- D$\frac{19}{2}$ square units
Solution
$O A B$ is triangle.

$\begin{aligned} \text { Area of triangle } & =\frac{1}{2} \times \text { base } \times \text { height }=\frac{1}{2} \times \mathrm{AB} \times \mathrm{OP} \\ & =\frac{1}{2} \times \frac{3}{2} \times 9=\frac{27}{4} \end{aligned}$ Area of triangle $=\frac{27}{4}$ square units

$\begin{aligned} \text { Area of triangle } & =\frac{1}{2} \times \text { base } \times \text { height }=\frac{1}{2} \times \mathrm{AB} \times \mathrm{OP} \\ & =\frac{1}{2} \times \frac{3}{2} \times 9=\frac{27}{4} \end{aligned}$ Area of triangle $=\frac{27}{4}$ square units
Hence, the correct answer is option: 'A'.