Consider the given sequence of reactions. $\mathrm{C}_2 \mathrm{H}_6+\frac{3}{2} \mathrm{O}_2 \xrightarrow[\Delta]{\left(\mathrm{CH}_3 \mathrm{COO}\right)_2 \mathrm{Mn}} \mathrm{X} \xrightarrow{\mathrm{Na}} \mathrm{Y}$ Electrolysis of aqueous solution of Y gives gases P and Q at anode. P and Q are respectively.

• Correct answer
  A

  $\mathrm{C}_2 \mathrm{H}_6, \mathrm{CO}_2$
• B

  $\mathrm{CH}_4, \mathrm{CO}_2$
• C

  $\mathrm{C}_2 \mathrm{H}_6, \mathrm{H}_2$
• D

  $\mathrm{CH}_4, \mathrm{CO}$

Hence, the correct answer is option: 'A'.