Q153 / 270 · NDA 2014 (Phase 2) · Mathematics

Consider the function $f(x)=\left\{\begin{aligned} x^2-5, & x \leq 3 \\ \sqrt{x+13}, & x \gt 3\end{aligned}\right.$ What is the differential coefficient of $f(x)$ at $x=12$ ?

  • A
    $\frac{5}{2}$
  • B
    5
  • C
    $\frac{1}{5}$
  • Correct answer
    D
    $\frac{1}{10}$

Solution

The correct answer is option (D)

Hence, the correct answer is option: 'D'.

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