Q104 / 160 · TS EAMCET 2025 (02 May Shift 2) · Mathematics
Consider the following statements
Assertion (A): For $x \in \mathbb{R}-\{1\}, \frac{d}{d x}\left(\operatorname{Tan}^{-1}\left(\frac{1+x}{1-x}\right)\right)=\frac{d}{d x}\left(\operatorname{Tan}^{-1} x\right)$
Reason (R): For $x < 1, \operatorname{Tan}^{-1}\left(\frac{1+x}{1-x}\right)=\frac{\pi}{4}+\operatorname{Tan}^{-1} x$,
for $x>1, \operatorname{Tan}^{-1}\left(\frac{1+x}{1-x}\right)=-\frac{3 \pi}{4}+\operatorname{Tan}^{-1} x$
The correct answer is
- Correct answerABoth (A) and (R) are true, (R) is the correct explanation of (A)
- BBoth (A) and (R) are true, (R) is not the correct explanation of (A)
- C(A) is true, but (R) is false
- D(A) is false, but (R) is true
Hence, the correct answer is option: 'A'.