Q39 / 180 · JIPMER 2017 · Chemistry

Consider the following solutions, $A=0.1 \mathrm{M}$ glucose, $B=0.05$ M $\mathrm{NaCl}$, $C=0.05$ M $\mathrm{BaCl}_2$, $D=0.1 \mathrm{M}$ $\mathrm{AlCl}_3$ Which of the following pairs is isotonic?

  • Correct answer
    A
    A and B
  • B
    A and D
  • C
    A and C
  • D
    B and C

Solution

Isotonic solutions have same molar concentration of solute particles in solution. Molar concentration of particles in solution are (a) = 0.1 M in glucose (b) $=2 \times 0.05 \mathrm{M}$ in NaCl (c) $=3 \times 0.05 \mathrm{M}$ in $\mathrm{BaCl}_2$ (d) $=4 \times 0.1 \mathrm{M}$ in $\mathrm{AlCl}_3$ Hence, 0.1 M glucose and 0.05 M NaCl solutions are isotonic.

Hence, the correct answer is option: 'A'.

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