Consider the following sequence of reactions:
11.25 mg of chlorobenzene will produce __________ $\times 10^{-1} \mathrm{mg}$ of product B . (Consider the reactions result in complete conversion.) [Given molar mass of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N}$ and Cl as $12,1,16,14$ and $35.5 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively]

Solution

$\begin{aligned} & \frac{11.25 \times 10^{-3}}{112.5}=\frac{x \times 10^{-1} \times 10^{-3}}{93} \\ & x \times 10^{-1}=93 \times 0.1 \\ & x=93 \mathrm{mg}\end{aligned}$

Hence, the correct answer is 93.