Q140 / 270 · NDA 2017 (Phase 2) · General Ability

Consider the following reaction: $\mathrm{CH}_4+2 \mathrm{O}_2 \longrightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}$ Which of the following about the reaction given above is/are correct? 1. Carbon is oxidized. 2. Hydrogen is oxidized. 3. Hydrogen is reduced. 4. Carbon is reduced. Select the correct answer using the code given below:

  • A
    $1$ only
  • Correct answer
    B
    $1$ and $2$ only
  • C
    $2$ and $3$ only
  • D
    $2$ and $4$ only

Solution

Oxidation: Gain of oxygen or loss of hydrogen; Loss of electrons or increase in oxidation state Reduction: Gain of hydrogen or loss of oxygen; Gain of electrons or decrease in oxidation state. In the combustion of methane, carbon loses hydrogen and gains oxygen, so it is being oxidized. Oxygen gains hydrogen (and carbon), so it is being reduced. Hydrogen gains oxygen (and loses carbon), so it is being oxidized.

Hence, the correct answer is option: 'B'.

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