Consider the following reaction sequence
The correct statements about $\mathrm{Z}$ are I. It gives yellow precipitate with $\mathrm{I}_2$ and $\mathrm{NaOH}$ solution II. It undergoes disproportionation reaction in the presence of concentrated $\mathrm{NaOH}$ solution III. It undergoes wolff-Kishner reduction IV. It forms red precipitate with Fehling's reagent

• A

  I & II only
• B

  II & III only
• C

  I & IV only
• Correct answer
  D

  I & III only

Solution

Since ' $\mathrm{Z}$ ' is a methyl ketone, it gives positive iodoform test and gives a yellow precipitate with $\mathrm{I}_2$ and $\mathrm{NaOH}$. Aldehydes and ketones undergo walff-kishner reduction to give the corresponding hydrocarbon. Thus, I and III are correct.,

Hence, the correct answer is option: 'D'.