Q31 / 60 · IAT (IISER) 2024 · Mathematics
Consider the following lines in the $X Y$-plane:
$L_1: 5 x-2 y=1$
$L_2$ : the line passing through $(0,1)$ and $(100,101)$,
$L_3$ : the line passing through $(1,11)$ and parallel to the vector $-\widehat{i}+2 \widehat{j}$.
Let $A=\left(L_1 \cap L_2\right) \cup\left(L_2 \cap L_3\right) \cup\left(L_3 \cap L_1\right)$. What is the total number of elements of $A$ ?
$L_1: 5 x-2 y=1$
$L_2$ : the line passing through $(0,1)$ and $(100,101)$,
$L_3$ : the line passing through $(1,11)$ and parallel to the vector $-\widehat{i}+2 \widehat{j}$.
Let $A=\left(L_1 \cap L_2\right) \cup\left(L_2 \cap L_3\right) \cup\left(L_3 \cap L_1\right)$. What is the total number of elements of $A$ ?
- A2
- Correct answerB3
- C0
- D1
Hence, the correct answer is option: 'B'.