Consider the following frequency distribution :

class $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$

Frequency $α$ $110$ $54$ $30$ $β$

If the sum of all frequencies is $584$ and median is $45$ , then $| α - β |$ is equal to .

Question

Consider the following frequency distribution : class 10-20 20-30 30-40 40-50 50-60 Frequency α 110 54 30 β If the sum of all frequencies is 584 and median is 45, then |α-β| is equal to .

MARKS Content Team · Accepted Answer

Correct answer: 164. ∵ Sum of frequencies =584 α+110+54+30+β=584 ⇒α+β=390 ...1 Now, Median is at 584/2=292^th term ∵ Median =45 (lies in class 40-50) ⇒α+110+54+15=292 ⇒α=113 ...2 On solving, equations 1 and2, we get ⇒α=113 & β=390-113=277 ⇒|α-β|=164

Consider the following frequency distribution :

class $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$

Frequency $α$ $110$ $54$ $30$ $β$

If the sum of all frequencies is $584$ and median is $45$ , then $| α - β |$ is equal to .

Solution

Relevant Questions

class	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Frequency	$α$	$110$	$54$	$30$	$β$