Q102 / 270 · NDA 2016 (Phase 1) · General Ability
Consider the following circuit:
The equivalent resistance of the circuit will be
The equivalent resistance of the circuit will be
- A$12 \Omega$
- B$8 \frac{11}{12} \Omega$
- Correct answerC$9 \frac{1}{11} \Omega$
- D$\frac{24}{25} \Omega$
Solution
$\begin{aligned}
& 1 / \mathrm{R}=1 / \mathrm{R}_1+1 / \mathrm{R}_2+1 / \mathrm{R}_3 \\
& =1 / 2+1 / 4+1 / 6 \\
& =11 / 12 \\
& \mathrm{R}=12 / 11
\end{aligned}$
Total resistance $=12 / 11+8=9~~1 / 11 \mathrm{~ohm}$.
Hence, the correct answer is option: 'C'.