Q170 / 270 · NDA 2014 (Phase 2) · Mathematics

Consider the circles $x^2+y^2+2 a x+c=0$ and $x^2+y^2+2 b y+c=0$. The two circles touch each other if

  • A
    $c=\sqrt{a^2+b^2}$
  • Correct answer
    B
    $\frac{1}{c}=\frac{1}{a^2}+\frac{1}{b^2}$
  • C
    $c=\frac{1}{a^2}+\frac{1}{b^2}$
  • D
    $c=\frac{1}{a^2+b^2}$

Solution

The correct answer is option(B)

Hence, the correct answer is option: 'B'.

More Circle Questions