Q170 / 270 · NDA 2014 (Phase 2) · Mathematics
Consider the circles $x^2+y^2+2 a x+c=0$ and $x^2+y^2+2 b y+c=0$.
The two circles touch each other if
- A$c=\sqrt{a^2+b^2}$
- Correct answerB$\frac{1}{c}=\frac{1}{a^2}+\frac{1}{b^2}$
- C$c=\frac{1}{a^2}+\frac{1}{b^2}$
- D$c=\frac{1}{a^2+b^2}$
Solution
The correct answer is option(B)
Hence, the correct answer is option: 'B'.