Consider ' $n$ ' is the number of lone pair of electrons present in the equatorial position of the most stable structure of $\mathrm{ClF}_3$. The ions from the following with ' $n$ ' number of unpaired electrons are A. $\mathrm{V}^{3+}$ B. $\mathrm{Ti}^{3+}$ C. $\mathrm{Cu}^{2+}$ D. $\mathrm{Ni}^{2+}$ E. $\mathrm{Ti}^{2+}$ Choose the correct answer from the options given below:

• A

  A and C Only
• Correct answer
  B

  A, D and E Only
• C

  B and D Only
• D

  B and C Only

Solution

$\mathrm{ClF}_3$
$\mathrm{n}=2($ No of lone pair present in equitorial plane $)$ (Unpaired $\mathrm{e}^{-}$) (A) $\mathrm{V}^{+3}:[\mathrm{Ar}] 3 \mathrm{~d}^2 \quad 2$ (B) $\mathrm{Ti}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^1 \quad 1$ (C) $\mathrm{Cu}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^9 \quad 1$ (D) $\mathrm{Ni}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^8 \quad 2$ (E) $\mathrm{Ti}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^2 \quad 2$

Hence, the correct answer is option: 'B'.