Consider an expression QV=kPTL^(α) where V, P, T, L are volume, pressure, time, and length respectively. The quantity Q has dimension ML^(-1) T^(-1)…

Question

Consider an expression QV=kPTL^(α) where V, P, T, L are volume, pressure, time, and length respectively. The quantity Q has dimension ML^(-1) T^(-1). k is a dimensionless constant. The value of the integer α is:

MARKS Content Team · Accepted Answer

Correct answer: (C) 3. The expression given in the question is, QV=kPTL^(α), here the dimension of pressure, volume, time and length are, ML^(-1)T^(-2), L^3, T & L, it means, QV=kPTL^(α)⇒ML^(-1) T^(-1)L^3=ML^(-1)T^(-2)×T×L^(α)⇒ML^2 T^(-1)=ML^(-1+α) T^(-1) On comparing the equation at both sides, -1+α=2⇒α=3.

Consider an expression $Q V = k P T L^{α}$ where $V, P, T, L$ are volume, pressure, time, and length respectively. The quantity $[Q]$ has dimension $M L^{- 1} T^{- 1} . k$ is a dimensionless constant. The value of the integer $α$ is:

Solution

Relevant Questions

Consider an expression QV=kPTLα where V, P, T, L are volume, pressure, time, and length respectively. The quantity Q has dimension ML-1 T-1. k is a dimensionless constant. The value of the integer α is:

Solution

Relevant Questions

Consider an expression $Q V = k P T L^{α}$ where $V, P, T, L$ are volume, pressure, time, and length respectively. The quantity $[Q]$ has dimension $M L^{- 1} T^{- 1} . k$ is a dimensionless constant. The value of the integer $α$ is: