Q156 / 160 · TS EAMCET 2018 (05 May Shift 1) · Physics

Consider an electron revolving in a circular orbit of hydrogen atom, whose quantum number is $n=2$. The velocity of the electron in that orbit is

Correct answer
A
$1.1 \times 10^6 \mathrm{~m} / \mathrm{s}$
B
$2.2 \times 10^7 \mathrm{~m} / \mathrm{s}$
C
$4.4 \times 10^6 \mathrm{~m} / \mathrm{s}$
D
$2.2 \times 10^5 \mathrm{~m} / \mathrm{s}$

Solution

Velocity of electron of $\mathrm{H}$ - atom in $n^{\text {th }}$ orbit is $v_n=\frac{v_1}{n}=\frac{22 \times 10^6}{2}=1.1 \times 10^6 \mathrm{~ms}^{-1}$

Hence, the correct answer is option: 'A'.

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