Q108 / 150 · JEE Main 2006 · Physics
Consider a two particle system with particles having masses $m_1$ and $m_2$. If the first particle is pushed towards the centre of mass through a distance $d$, by what distance should the second particle be moved, so as to keep the centre of mass at the same position?
- A$\mathrm{d}$
- B$\frac{m_2}{m_1} \mathrm{~d}$
- C$\frac{m_1}{m_1+m_2} d$
- Correct answerD$\frac{\mathrm{m}_1}{\mathrm{~m}_2} \mathrm{~d}$
Solution
$m_1 d+m_2 x=0$
$x=\frac{m_1 d}{m_2}$
Hence, the correct answer is option: 'D'.