Q108 / 150 · JEE Main 2006 · Physics

Consider a two particle system with particles having masses $m_1$ and $m_2$. If the first particle is pushed towards the centre of mass through a distance $d$, by what distance should the second particle be moved, so as to keep the centre of mass at the same position?

  • A
    $\mathrm{d}$
  • B
    $\frac{m_2}{m_1} \mathrm{~d}$
  • C
    $\frac{m_1}{m_1+m_2} d$
  • Correct answer
    D
    $\frac{\mathrm{m}_1}{\mathrm{~m}_2} \mathrm{~d}$

Solution

$m_1 d+m_2 x=0$ $x=\frac{m_1 d}{m_2}$

Hence, the correct answer is option: 'D'.

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