Consider a parallelogram whose vertices are A(1,2), B (4, $y), C(x, 6)$ and $D(3,5)$ taken in order. What is the point of intersection of the diagonals?

• Correct answer
  A

  $\left(\frac{7}{2}, 4\right)$
• B

  $(3,4)$
• C

  $\left(\frac{7}{2}, 5\right)$
• D

  $(3,5)$

Hence, the correct answer is option: 'A'.