Q36 / 90 · JEE Main 2021 (18 Mar Shift 2) · Mathematics

Consider a hyperbola H : x2-2y2=4. Let the tangent at a point P(4,6) meet the x-axis at Q and latus rectum at Rx1,y1,x1>0. If F is a focus of H which is nearer to the point P, then the area of ΔQFR (in sq. units) is equal to

  • A
    46
  • B
    6-1
  • Correct answer
    C
    76-2
  • D
    46-1

Solution

Figure

x24-y22=1

e=1+b2a2=32

∴ Focus F(ae,0)⇒F(6,0)

equation of tangent at P to the hyperbola is
2x-y6=2

tangent meet x-axis at Q(1,0)

& latus rectum x=6 at R6,266-1

∴ Area of ΔQFR=126-1·266-1

=76-2 sq. units

Hence, the correct answer is option: 'C'.

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