Q143 / 160 · TS EAMCET 2020 (14 Sep Shift 2) · Physics
Consider a glass prism immersed in a liquid as shown below. The refractive index of glass and liquid is 1.5 and 1.2, respectively. A ray of light enters the prism perpendicular to the face $A B$. The largest value of angle $\theta$ is, if the ray is totally reflected at the face $A C$, then


- Correct answerA$\cos ^{-1}(0.8)$
- B$\sin ^{-1}(0.8)$
- C$\cos ^{-1}(0.6)$
- D$\sin ^{-1}(0.4)$
Solution
The given situation is shown in the following figure.

For the ray incident at face $A C$ to be total internally reflected, if Angle of incidence $=$ Critical angle $\begin{aligned} & \Rightarrow \quad i=i_c \Rightarrow \sin (i)=\sin \left(i_c\right) \\ & \Rightarrow \quad \sin (90-\theta)=\frac{\mu_{\text {rarer }}}{\mu_{\text {denser }}} \\ & \Rightarrow \quad \cos (\theta)=\frac{\mu_l}{\mu_g} \Rightarrow \cos (\theta)=\frac{1.2}{1.5} \\ & \Rightarrow \quad \cos \theta=\frac{4}{5} \Rightarrow \cos \theta=0.8 \Rightarrow \theta=\cos ^{-1}(0.8) \end{aligned}$

For the ray incident at face $A C$ to be total internally reflected, if Angle of incidence $=$ Critical angle $\begin{aligned} & \Rightarrow \quad i=i_c \Rightarrow \sin (i)=\sin \left(i_c\right) \\ & \Rightarrow \quad \sin (90-\theta)=\frac{\mu_{\text {rarer }}}{\mu_{\text {denser }}} \\ & \Rightarrow \quad \cos (\theta)=\frac{\mu_l}{\mu_g} \Rightarrow \cos (\theta)=\frac{1.2}{1.5} \\ & \Rightarrow \quad \cos \theta=\frac{4}{5} \Rightarrow \cos \theta=0.8 \Rightarrow \theta=\cos ^{-1}(0.8) \end{aligned}$
Hence, the correct answer is option: 'A'.