Conductivity of a photodiode starts changing only if the wavelength of incident light is less than 660 nm. The band gap of photodiode is found to be…

Question

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than $660 nm .$ The band gap of photodiode is found to be $(\frac{X}{8}) eV .$ The value of $X$ is:

(Given $h = 6.6 \times 10^{- 34} J s, e = 1.6 \times 10^{- 19} C$ )

MARKS Content Team · Accepted Answer

Correct answer: (A) 15. Given: Threshold wavelength =660 nm. Therefore, energy required(or band gap energy) E_g=hc/(λ)=(6.6×10^(-34)×3×10^8)/(660×10^(-9)) J =(6.6×10^(-34)×3×10^8)/(660×10^(-9)×1.6×10^(-19)) eV =15/8eV So, X=15.

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than $660 nm .$ The band gap of photodiode is found to be $(\frac{X}{8}) eV .$ The value of $X$ is:
(Given $h = 6.6 \times 10^{- 34} J s, e = 1.6 \times 10^{- 19} C$ )

Solution

Relevant Questions

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than 660 nm. The band gap of photodiode is found to be X8 eV. The value of X is:(Given h=6.6×10-34 J s, e=1.6×10-19 C)

Solution

Relevant Questions

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than $660 nm .$ The band gap of photodiode is found to be $(\frac{X}{8}) eV .$ The value of $X$ is:
(Given $h = 6.6 \times 10^{- 34} J s, e = 1.6 \times 10^{- 19} C$ )