Q42 / 180 · COMEDK 2025 (10 May Shift 2) · Chemistry
Complete the following 2 reactions A & B by choosing appropriate reactants \([\mathrm{X}]\) & \([\mathrm{Y}]\).


- Correct answerA\([\mathrm{X}]=\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH} \quad [\mathrm{Y}]=\mathrm{C}_6 \mathrm{H}_5-\mathrm{N}-\left(\mathrm{CH}_3\right)_2\)
- B\([\mathrm{X}]=\mathrm{C}_6 \mathrm{H}_5 \mathrm{Br} \quad [\mathrm{Y}]=\mathrm{CH}_3 \mathrm{CH}_2-\mathrm{N}-\left(\mathrm{CH}_3\right)_2\)
- C\([\mathrm{X}]=\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO} \quad[\mathrm{Y}]=\mathrm{CH}_3-\mathrm{CO}-\mathrm{CH}_3\)
- D\([\mathrm{X}]=\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2 \quad[\mathrm{Y}]=\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}\)
Solution
The reactions shown are electrophilic aromatic substitution reactions, specifically diazo coupling reactions between a diazonium salt and an activated aromatic ring.
In reaction A, benzenediazonium chloride reacts with [X] to form p-hydroxyazobenzene. This is a coupling reaction with phenol ($\text{C}_6\text{H}_5\text{OH}$) in an alkaline medium (indicated by $\text{OH}^{-}$). The phenol acts as the nucleophile, attacking the diazonium cation at the para position.
In reaction B, benzenediazonium chloride reacts with [Y] to form p-dimethylaminoazobenzene. This is a coupling reaction with N,N-dimethylaniline ($\text{C}_6\text{H}_5\text{N}(\text{CH}_3)_2$) in an acidic medium (indicated by $\text{H}^{+}$). The dimethylamino group activates the benzene ring towards electrophilic substitution at the para position.
Comparing these with the given options, [X] corresponds to $\text{C}_6\text{H}_5\text{OH}$ and [Y] corresponds to $\text{C}_6\text{H}_5\text{N}(\text{CH}_3)_2$.
Answer: $[\mathrm{X}] = \mathrm{C}_6\mathrm{H}_5\mathrm{OH} \quad [\mathrm{Y}] = \mathrm{C}_6\mathrm{H}_5\mathrm{N}(\mathrm{CH}_3)_2$
Hence, the correct answer is option: 'A'.