Q10 / 54 · JEE Advanced 2020 (Paper 2) · Chemistry

Choose the correct statement(s) among the following.

Correct answer
A
${SnCl}_{2} \cdot 2 H_{2} O$ is a reducing agent.
Correct answer
B
${SnO}_{2}$ reacts with $KOH$ to form $K_{2} [Sn (OH)_{6}]$
C
A solution of ${PbCl}_{2}$ in $HCl$ contains ${Pb}^{2 +}$ and ${Cl}^{-}$ ions.
D
The reaction of ${Pb}_{3} O_{4}$ with hot dilute nitric acid to give ${PbO}_{2}$ is a redox reaction.

Solution

(A) ${Sn}^{2 +}$ is a good reducing agent which gets oxidise into ${Sn}^{4 +}$

(B) Amphoteric nature.

(D) $\underset{(2 PbO + {PbO}_{2})}{{Pb}_{3} O_{4}} + \underset{(Conc .)}{4 {HNO}_{3}} \to {PbO}_{2} ↓ + 2 Pb {({NO}_{3})}_{2} + 6 H_{2} O$

Hence, the correct answer is options: 'A', 'B'.