Charges $-q$ and $+q$, located at $A$ and $B$, respectively, constitute an electric dipole. Distance $AB=2a$, $O$ is the mid point of the dipole and $OP$ is perpendicular to $AB$. A charge $Q$ is placed at $P$ where $OP=y$ and $y\gg 2a$. The charge $Q$ experiences an electrostatic force $F$. If $Q$ is now moved along the equatorial line to $P\text{'}$ such that $OP\text{'}=\left(\frac{y}{3}\right)$ the force on $Q$ will be close to$\left(\frac{y}{3}\ll 2a\right)$

• Correct answer
  A

  $27F$.
• B

  $\frac{F}{3}$.
• C

  $3F$.
• D

  $9F$.

Hence, the correct answer is option: 'A'.