Q144 / 160 · TS EAMCET 2022 (19 Jul Shift 2) · Physics

$6 \mu C$ charge is placed at the centre of a cube. What will be the electric flux at each face of the tube? $$ \left[\text { Take } \frac{1}{4 \pi \epsilon_o}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right] $$

  • A
    $9 \pi \times 10^2 \mathrm{Nm}^2 / \mathrm{C}$
  • Correct answer
    B
    $36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}$
  • C
    $3.6 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}$
  • D
    $4 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}$

Solution

$\begin{aligned} & \left.\phi_{\text {net }}\right|_{\text {side }}=\frac{q_{\text {net }}}{6 \epsilon_0} \\ & =\frac{6 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}} \\ & =112994.35 \\ & \simeq 36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\end{aligned}$

Hence, the correct answer is option: 'B'.

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