CH_3 CH_2 COOH ⟶ red P Cl_2 Α ⟶ alc.KOH Β What is B ?

Correct answer: (D) CH2=CHCOOH. 1st step is Hell-Volhard Zelinsky reaction, halogenation of carboxylic acid at α - C CH_3 CH_2 COOH → red P - HCl Cl_2 CH_3 CHClCOOH → - HCl alc. KOH CH_2=CHCOOH Acrylic acid

Q15 / 66 · NTA Abhyas (JEE Main) 2020 · Chemistry · Carboxylic Acid Derivatives

${CH}_{3} {CH}_{2} COOH ⟶_{red P}^{{Cl}_{2}} Α \overset{alc.KOH}{⟶} Β$
What is B ?

A
CH₃CH₂COCl
B
CH₃CH₂CHO
C
ClCH₂CH₂COOH
Correct answer
D
CH₂=CHCOOH

Solution

1st step is Hell-Volhard Zelinsky reaction, halogenation of carboxylic acid at

α​ - C

\begin{matrix} {CH}_{3} {CH}_{2} COOH & \to_{\underset{- HCl}{red P}}^{{Cl}_{2}} & {CH}_{3} CHClCOOH & \to_{- HCl}^{alc. KOH} \end{matrix}

\begin{matrix} C H_{2} = C H C O O H \\ A c r y l i c a c i d \end{matrix}

Hence, the correct answer is option: 'D'.

CH 3 CH 2 COOH ⟶ red P Cl 2 Α ⟶ alc.KOH Β What is B ?

Solution

More Carboxylic Acid Derivatives Questions

${CH}_{3} {CH}_{2} COOH ⟶_{red P}^{{Cl}_{2}} Α \overset{alc.KOH}{⟶} Β$
What is B ?