Capacitance of an isolated conducting sphere of radius R_1 becomes n times when it is enclosed by a concentric conducting sphere of radius R_2…

Question

Capacitance of an isolated conducting sphere of radius R_1 becomes n times when it is enclosed by a concentric conducting sphere of radius R_2 connected to earth. The ratio of their radii R_2R_1 is:

MARKS Content Team · Accepted Answer

Correct answer: (A) n/(n-1). Capacitance of isolated conducting sphere C=4πε_0R_1 By enclosing inside another sphere of radius R_2, new capacitance C^(')=(4πε_0R_1R_2)/(R_2-R_1) Given: (4πε_0R_1R_2)/(R_2-R_1)=n×4πε_0R_1 ⇒R_2R_2-R_1=n⇒R_2R_1/(R_2R_1-1)=n ⇒R_2R_1=nR_2R_1-n⇒R_2R_1=n/(n-1)

Capacitance of an isolated conducting sphere of radius $R_{1}$ becomes $n$ times when it is enclosed by a concentric conducting sphere of radius $R_{2}$ connected to earth. The ratio of their radii $(\frac{R_{2}}{R_{1}})$ is:

Solution

Relevant Questions

Capacitance of an isolated conducting sphere of radius R1 becomes n times when it is enclosed by a concentric conducting sphere of radius R2 connected to earth. The ratio of their radii R2R1 is:

Solution

Relevant Questions

Capacitance of an isolated conducting sphere of radius $R_{1}$ becomes $n$ times when it is enclosed by a concentric conducting sphere of radius $R_{2}$ connected to earth. The ratio of their radii $(\frac{R_{2}}{R_{1}})$ is: