Q66 / 200 · NEET 2006 · Chemistry

$\mathrm{Al}_2 \mathrm{O}_3$ can be converted to anhydrous $\mathrm{AlCl}_3$ by heating:

  • A
    $\mathrm{Al}_2 \mathrm{O}_3$ with $\mathrm{Cl}_2$ gas
  • B
    $\mathrm{Al}_2 \mathrm{O}_3$ with $\mathrm{HCl}$ gas
  • C
    $\mathrm{Al}_2 \mathrm{O}_3$ with $\mathrm{NaCl}$ in solid state
  • Correct answer
    D
    A mixture of $\mathrm{Al}_2 \mathrm{O}_3$ and carbon in dry $\mathrm{Cl}_2$ gas

Solution

$\mathrm{Al}_2 \mathrm{O}_3$ may be converted to anhydrous $\mathrm{AlCl}_3$ by heating a mixture of $\mathrm{Al}_2 \mathrm{O}_3$ and carbon in dry chlorine. $\mathrm{Al}_2 \mathrm{O}_3+3 \mathrm{C}+3 \mathrm{Cl}_2 \rightarrow \underset{\text {(anhydrous } \mathrm{AlCl}_3)}{\mathrm{Al}_2 \mathrm{Cl}_6}$

Hence, the correct answer is option: 'D'.

More p Block Elements (Group 13 & 14) Questions