Q31 / 160 · AP EAMCET 2022 (05 Jul Shift 2) · Chemistry

Calculated magnetic moment value for $\mathrm{Fe}^{2+}$ ion in $\mathrm{BM}$ is

  • A
    $3.87$
  • Correct answer
    B
    $4.90$
  • C
    $2.84$
  • D
    $1.73$

Solution

$\mathrm{Fe}^{2+}\left(\mathrm{d}^6\right):$ Unpaired electrons $(\mathrm{n})=4$ $\therefore \quad \mu_{\text {s.o. }}=\sqrt{4(4+2)}=2 \sqrt{6}=4.89 \simeq 4.90 \mathrm{BM}$

Hence, the correct answer is option: 'B'.

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