Q12 / 160 · TS EAMCET 2022 (20 Jul Shift 2) · Chemistry
Calculate the value of the equilibrium constant $\left(\mathrm{K}_{\mathrm{p}}\right)$ for the reaction of oxygen gas oxidising ammonia gas to nitric oxide and water vapour. The pressure of each gas at equilibrium is $0.5 \mathrm{~atm}$.
- A$1.5 \mathrm{~atm}$
- Correct answerB$0.5 \mathrm{~atm}$
- C$1 \mathrm{~atm}$
- D$2.5 \mathrm{~atm}$
Solution
$4 \mathrm{NH}_3 \uparrow+5 \mathrm{O}_2 \uparrow \longrightarrow 4 \mathrm{NO} \uparrow+6 \mathrm{H}_2 \mathrm{O} \uparrow$
$\mathrm{K}_{\mathrm{p}}=\frac{\mathrm{p}_{\mathrm{NO}}^4 \mathrm{p}_{\mathrm{H}_2 \mathrm{O}}^6}{\mathrm{P}_{\mathrm{NH}_3}^4 \mathrm{p}_{\mathrm{O}_2}^5}=\frac{(0.5)^{10}}{(0.5)^9}=0.5 \mathrm{~atm}$
Hence, the correct answer is option: 'B'.