Q46 / 150 · MHT CET 2025 (21 Apr Shift 1) · Chemistry

Calculate the total number of tetrahedral and octahedral voids in 0.4 mol compound having such voids in it.

  • A
    $2.4088 \times 10^{23}$
  • Correct answer
    B
    $7.2264 \times 10^{23}$
  • C
    $4.8176 \times 10^{23}$
  • D
    $9.6352 \times 10^{23}$

Solution

The total number of voids in a close-packed structure depends on the number of constituent particles. For N particles, there are N octahedral voids and 2N tetrahedral voids, giving a total of 3N voids.

With 0.4 mol of the compound, the number of particles is $N = 0.4 \times 6.022 \times 10^{23} = 2.4088 \times 10^{23}$.

The total void count is therefore $3N = 3 \times 2.4088 \times 10^{23} = 7.2264 \times 10^{23}$, corresponding to option B.

Hence, the correct answer is option: 'B'.

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