Q44 / 150 · MHT CET 2022 (05 Aug Shift 1) · Chemistry

Calculate the pressure of gas if the solubility of gas in water at $25^{\circ} \mathrm{C}$ is $6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3}$ (Henry's law constant is $6.85 \times 10^4 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}$ )

  • Correct answer
    A
    0.853 bar
  • B
    $1.5 \mathrm{bar}$
  • C
    0.5 bar
  • D
    1 bar

Solution

We know $$ \mathrm{S}=\mathrm{K}_{\mathrm{H}} \mathrm{P} $$ In $1 \mathrm{dm}^3$ or 1 lit moles of gas dissolved is $6.85 \times 10^4$ $\therefore \mathrm{p}=6.85 \times 10^4 / 6.85 \times 10^4=1.0$ bar.

Hence, the correct answer is option: 'A'.

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