Calculate the number of moles of the gas having volume 2.5 liter at 300 ~K and 4.5 ~atm ? (R=0.0821 ~atm dm^3 ~K^-1 ~mol^-1 )

Correct answer: (B) 0.46. PV=nRT 4.5 × 2.5=n × 0.0821 × 300 n=0.56

Q37 / 150 · MHT CET 2022 (07 Aug Shift 1) · Chemistry

Calculate the number of moles of the gas having volume 2.5 liter at $300 \mathrm{~K}$ and $4.5 \mathrm{~atm}$ ? $\left(\mathrm{R}=0.0821 \mathrm{~atm} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$

$\begin{aligned} & \mathrm{PV}=\mathrm{nRT} \\ & 4.5 \times 2.5=\mathrm{n} \times 0.0821 \times 300 \\ & \mathrm{n}=0.56\end{aligned}$

Hence, the correct answer is option: 'B'.