Q39 / 73 · NTA Abhyas (JEE Main) 2020 · Chemistry · Some Basic Concepts of Chemistry

Calculate the minimum mass of ${C l}_{2}$ in grams required to produce $37 .25 g KCl?$

$C l_{2} + 2 K O H \to K C l + K C l O + H_{2} O$

Correct answer: 35.5

Solution

C l_{2} + 2 K O H \to K C l + K C l O + H_{2} O

37 .25 g

\frac{37.25}{74.5} m o l

0.5 m o l K C l

Mole of

{C l}_{2}

required =

0 .5 mol

Mass of

{C l}_{2}

required

= 0.5 \times 71 = 35.5 g

Hence, the correct answer is 35.5.

More Some Basic Concepts of Chemistry Questions

A crystalline hydrated salt on being heated loses 45.6% of its weight. Percentage composition of anhydrous salt is Al - 10.5 %, K - 15.1 %,
At 100 o C and 1 atm. if the density of liquid water is 1.0 gc m - 3 and that of water vapour is 0.0006 gc m - 3 , then the volume occupied
A carbon compound contains 12.8% of carbon, 2.1% of hydrogen and 85.1% of bromine. The molecular weight of the compound is 187.9. Calculate
1 g of a complex [Cr(H 2 O) 5 Cl]Cl 2 ⋅ H 2 O (mol. Wt. 266.5) was passed through a cation exchanger to produce HCl . The acid liberated was
Aluminum carbide A l 4 C 3 liberates methane on treatment with water. The grams of aluminum carbide required to produce 11 .2 L of methane u
29.2 % w / w H C l stock solution has a density of 1.25 g m L - 1 . The molecular weight of H C l is 36.5 g mo l - 1 . The volume (mL) of st