Q34 / 150 · MHT CET 2022 (07 Aug Shift 1) · Chemistry
Calculate the edge length of unit cell that crystallises to form bcc structure. (Radius of atom is $2.17 \times 10^{-8} \mathrm{~cm}, \sqrt{3}=1.732$ )
- A$4.3 \times 10^{-8} \mathrm{~cm}$
- B$2.5 \times 10^{-8} \mathrm{~cm}$
- Correct answerC$5.0 \times 10^{-8} \mathrm{~cm}$
- D$3.1 \times 10^{-8} \mathrm{~cm}$
Solution
For B.C.C unit cell
$\begin{aligned} & \sqrt{3} \mathrm{a}=4 \mathrm{r} \\ & \mathrm{a}=\frac{4 \times 2.17 \times 10^{-8}}{\sqrt{3}}=5.0 \times 10^{-8} \mathrm{~cm}\end{aligned}$
Hence, the correct answer is option: 'C'.