Q133 / 180 · JIPMER 2018 · Physics

Calculate the dispersive power for crown glass from the given data $\begin{array}{rll} & \mu_{\mathrm{V}}=1.523 \\ \text { and } & \mu_{\mathrm{R}}=1.5145\end{array}$

  • Correct answer
    A
    $0.01639$
  • B
    $1.05639$
  • C
    $0.05639$
  • D
    $2.05639$

Solution

Here, $\mu_V=1.523$ and $\mu_R=1.5145$ Mean refractive index, $\mu=\frac{1.523+1.5145}{2}=1.51875$ Dispersive power is given by, $\begin{aligned} \omega & =\frac{\left(\mu_V-\mu_R\right)}{(\mu-1)} \\ & =\frac{1.523-1.5145}{(1.51875-1)}=0.01639\end{aligned}$

Hence, the correct answer is option: 'A'.

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